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17m^2-33m=0
a = 17; b = -33; c = 0;
Δ = b2-4ac
Δ = -332-4·17·0
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-33}{2*17}=\frac{0}{34} =0 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+33}{2*17}=\frac{66}{34} =1+16/17 $
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